It is given that $A$ and $B$ are such that $P(A) = \frac{1}{4}$,$P(A|B) = \frac{1}{2}$,and $P(B|A) = \frac{2}{3}$. Then $P(B) = $?

  • A
    $\frac{1}{3}$
  • B
    $\frac{2}{3}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{1}{6}$

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$(S1) P(A' \cup B) = \frac{5}{6}$
$(S2) P(A' \cap B') = \frac{1}{18}$.
Then:

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